[Chilli] [SOLVED] !!!!! Check_Item Is Always Equal To 0 When 2^32

[Russell Mike]

Dear Matthew & Alan DeKok.
Thank you ver very very much for your assistanc throughout. This worked
!!!!!

I am able to do it with help of your both. You guys are great. Honestly, it
was not possible for me without you help.

I will write the solution as one document to help others. Solution can
manage & control up to 2TB per voucher / username.

Once again, my special thanks to Alan D. & Matthew
Regards
RM--

On Thursday, October 24, 2013, Matthew Newton wrote:

> On Thu, Oct 24, 2013 at 11:35:30AM +0000, Russell Mike wrote:
> > >   I can't make it any clearer than that.
> >
> > thank you very very much, it is great explanation. Your response made
> > many things very clearer. But did not work for me still. Perhaps my
> formula
> > is wrong. Kindly help one more step further. Honestly, i have tried very
> > hard, working on it for some weeks now without results. i.e. i want to
> set
> > 6GB limit.
> >
> > total bytes in 6GB = 805306368
> > total bytes in 4GB = 536870912
>
> Not sure where you got these from.
>
> 6GB = 6 * 1024 * 1024 * 1024 = 4 * 1024^3 = 6442450944
>
> 6GB in binary is
>
> 0000000000000000000000000000000110000000000000000000000000000000
>
> 3210987654321098765432109876543210987654321098765432109876543210
>    6         5         4         3         2         1         0
>
> So the lower 32 bits are:
>
> 10000000000000000000000000000000
>
> and the upper 32 bits are:
>
> 00000000000000000000000000000001
>
> The lower bits can be found by bitwise AND with (2^32)-1 (i.e. 32
> ones):
>
> $ python
> >>> 6*(1024**3) & ((2**32)-1)
> 2147483648
>
> The upper 32 bits by shifting right by 32 bits:
>
> >>> 6*(1024**3) >> 32
> 1
>
>
> So you want
>
> > i put 536870912 in ChilliSpot-Max-Input-Octets
>
> this should be 2147483648;
>
> > i put 268435456 in ChilliSpot-Max-Input-Gigawords
>
> This should be 1.
>
> To confirm the numbers are correct, left-shift the gigawords by 32
> bits, then add the octets. Should come back to the original value:
>
> >>> (1<<32) + 2147483648
> 6442450944
> >>> 6*(1024**3)
> 6442450944
>
> Matthew
>
>
> --
> Matthew Newton, Ph.D. <mcn4 at le.ac.uk <javascript:;>>
>
> Systems Specialist, Infrastructure Services,
> I.T. Services, University of Leicester, Leicester LE1 7RH, United Kingdom
>
> For IT help contact helpdesk extn. 2253, <ithelp at le.ac.uk <javascript:;>>
> -
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